From ad63d0a98d8595d3267fd81196cf8c96361bd911 Mon Sep 17 00:00:00 2001 From: Franciszek Malinka Date: Mon, 11 Jul 2022 20:13:42 +0200 Subject: Updates updates --- sections/preliminaries.tex | 29 ++++++++++++++++++++++++++++- 1 file changed, 28 insertions(+), 1 deletion(-) (limited to 'sections/preliminaries.tex') diff --git a/sections/preliminaries.tex b/sections/preliminaries.tex index 82e64b4..05aa3ed 100644 --- a/sections/preliminaries.tex +++ b/sections/preliminaries.tex @@ -306,7 +306,11 @@ $\Obj(\cC)$, but most often simply as $\cC$) and collection of \emph{morphisms} $\Mor(A, B)$ between each pair of objects $A, B\in \cC$. We require that for each pair of morphisms $f\colon B\to C$, $g\colon A\to B$ there is a - morphism $f\circ g\colon A\to C$. For every $A\in\cC$ there is an + morphism $f\circ g\colon A\to C$. If $f\colon A\to B$ then we say + that $A$ is the domain of $f$ ($\dom{f}$) and that $B$ is the range of + $f$ ($\rng{f}$). + + For every $A\in\cC$ there is an \emph{identity morphism} $\id_A$ such that for any morphism $f\in \Mor(A, B)$ we have that $f\circ id_A = \id_B \circ f$. @@ -349,6 +353,29 @@ \end{center} \end{definition} + Natural transformation has, \textit{nomen omen}, natural properties. One + particularly interesting to us is the following fact. + + \begin{fact} + Let $\eta$ be a natural transformation of functors $F, G$ from category + $\cC$ to $\cD$. Then $\eta$ is an isomorphism if and only if + all of the component morphisms are isomorphisms. + \end{fact} + + \begin{proof} + Suppose that $\eta_(A)$ is an isomorphism for every $A\in\cC$, where + $\eta_{A}\colon F(A)\to G(A)$ is the morphism of the natural transformation + coresponding to $A$. Then $\eta^{-1}$ is simply given by the morphisms + $\eta^{-1}_A$. + + Now assume that $\eta$ is an isomorphism, i.e. $\eta^{-1}\circ\eta = \id_F$. + \textit{Ad contrario} assume that there is $A\in\cC$ such that the component + morphism $\eta_A\colon F(A)\to G(A)$ is not an isomorphism. It means + that $\eta_A^{-1}\circ\eta_A \neq id_A$, hence + $F(A) = \dom(\eta^{-1}\circ\eta)(A) \neq \rng(\eta^{-1}\circ\eta)(A) = F(A)$, + which is obviously a contradiction. + \end{proof} + \begin{definition} In category theory, a \emph{diagram} of type $\mathcal{J}$ in category $\cC$ is a functor $D\colon \mathcal{J}\to\cC$. $\mathcal{J}$ is called the -- cgit v1.2.3